By David E. Malach
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Isaac Asimov (1920-1992), écrivain américain qui a marqué l. a. science-fiction, est mort depuis vingt ans. Pourtant l’intérêt pour son œuvre est toujours présent, comme en témoignent les activités qui signaleront le vingtième anniversaire de son décès.
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Extra info for Advances in Mechanical Engineering Research; Volume 2
M. M. (1967) Application of fracture mechanics to anisotropic plates, ASME J. Appl. Mech. Series E, 34 4, pp. 967-974. M. (2009) A continuum failure criterion applicable to wood. J. of Wood Sci, Vol. 5. 1007/s10086-009-1036-2) Gopu, Vijaya K. A. (1987) Validity of Distortion-Energy-Based Strength Criterion for Timber Members, J. Struc. Eng. 113, No. 12 pp. 2475-2487. 6. 1. Introduction The theory of total fracture energy, discussed in Section 5, was initially developed to obtain simple general design rules for beams with square end-notches and edge joints, loaded Fracture Mechanics of Wood and Wood-like Reinforced Polymers 35 perpendicular to the grain design rules of square notches and joints for the Dutch Building Code and later, as modification of the method of , published in  with the extensions for high beams.
8) Thus the energy of crack extension is equal to the increase of elastic energy. 9) where G f is the fracture energy per unit crack surface and ―bhd(β)‖ the crack surface increase with ―b‖ as width and ―h‖ the height of the beam with a crack length l = βh. 10) for the same crack length and now the energy of crack extension is equal to the decrease of elastic energy in the beam. 11) where again V 1 / 2 is the increase of the elastic energy and V ( 1 ) the plastic energy of the flow of the joint.
Derivation of the Power Law The power law may represent any function f(x) as follows from the following derivation. 3). Any function f(x) always can be written in a reduced variable x/x0 30 T. A. C. M. 7) and can be given in the power of a function: f ( x) f1 ( x / x0 ) f ( x) f ( x0 ) f ( x / x ) 1/ n n 1 0 and expanded into the row: x x0 . ( x x0 ) 2 . f '( x0 ) f ''( x0 ) ....... 1! 2! giving: n x x x0 1 1/ n 1/ n 1 f ( x) f1 (1) f1 (1) . f1 (1).